Answer:
42a. Ammeter 2 = 0.20 A
42b. Ammeter 3 = 0.20 A
42c. The current will remain the same i.e unchanged.
43. Equivalent resistance is 11780 Ω
46a. 11 V
46b. 7.5 V
46c. 18.5 V
47. 1.70 A
Step-by-step explanation:
42a. Determination of ammeter 2
Ammeter 1 = 0.20 A
Ammeter 2 =?
Since the resistors are in series connection, the same current will pass through them. Thus, ammeter 2 will read 0.20 A.
Ammeter 2 = ammeter 1 = 0.20 A
42b. Determination of ammeter 3
Ammeter 1 = 0.20 A
Ammeter 3 =?
Since the resistors are in series connection, the same current will pass through them. Thus, ammeter 3 will read 0.20 A.
Ammeter 3 = ammeter 1 = 0.20 A
42c. Since the resistors are in series connection, the same current will pass through them. Therefore, the current will remain the same.
43. Determination of the equivalent resistance.
We'll begin by converting 1.1 KΩ and 10 KΩ to Ω. This can be obtained as follow:
1 KΩ = 1000 Ω
Therefore,
1.1 KΩ = 1.1 KΩ × 1000 Ω / 1 KΩ
1.1 KΩ = 1100 Ω
1 KΩ = 1000 Ω
Therefore,
10 KΩ = 10 KΩ × 1000 Ω / 1 KΩ
10 KΩ = 10000 Ω
Finally, we shall determine determine the equivalent. This can be obtained as follow:
Resistor 1 (R₁) = 680 Ω
Resistor 2 (R₂) = 1100 Ω
Resistor 3 (R₃) = 10000 Ω
Equivalent Resistance (Rₑq) =?
Rₑq = R₁ + R₂ + R₃
Rₑq = 680 + 1100 + 10000
Rₑq = 11780 Ω
Thus, the equivalent resistance is 11780 Ω
46a. Determination of the voltage across 22 Ω
Current (I) = 0.50 A
Resistor (R₁) = 22 Ω
Voltage (V₁) =?
NOTE: the current is the same since the resistor are in series connection.
V₁ = IR₁
V₁ = 0.5 × 22
V₁ = 11 V
46b. Determination of the voltage across 15 Ω
Current (I) = 0.50 A
Resistor (R₂) = 15 Ω
Voltage (V₂) =?
NOTE: the current is the same since the resistor are in series connection.
V₂ = IR₂
V₂ = 0.5 × 15
V₂ = 7.5 V
46c. Determination of the voltage of the battery.
Voltage 1 (V₁) = 11 V
Voltage 2 (V₂) = 7.5 V
Battery voltage (V) =?
V = V₁ + V₂
V = 11 + 7.5
V = 18.5 V
47. Determination of the current.
We'll begin by calculating the equivalent resistance. This can be obtained as follow:
Resistor 1 (R₁) = 22 Ω
Resistor 2 (R₂) = 4.5 Ω
Equivalent Resistance (R) =?
R = R₁ + R₂
R = 22 + 4.5
R = 26.5 Ω
Finally, we shall determine the current.
Voltage (V) = 45 V
Resistance (R) = 26.5 Ω
Current (I) =?
V = IR
45 = I × 26.5
Divide both side by 26.5
I = 45 / 26.5
I = 1.70 A