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Peyton is going to invest $440 and leave it in an account for 5 years. Assuming the

interest is compounded annually, what interest rate, to the nearest tenth of a percent,
would be required in order for Peyton to end up with $520?

User YouEyeK
by
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1 Answer

3 votes

Answer:

The required interest rate would be of 3.4% a year.

Explanation:

The amount of money earned in compound interest, after t years, is given by:


P(t) = P(0)(1+r)^t

In which P(0) is the initial investment and r is the interest rate, as a decimal.

Peyton is going to invest $440 and leave it in an account for 5 years.

This means that
P(0) = 440, t = 5

So


P(t) = P(0)(1+r)^t


P(t) = 440(1+r)^5

What interest rate, to the nearest tenth of a percent, would be required in order for Peyton to end up with $520?

This is r for which P(t) = 520. So


P(t) = 440(1+r)^5


(1+r)^5 = (520)/(440)


\sqrt[5]{(1+r)^5} = \sqrt[5]{(52)/(44)}


1 + r = ((52)/(44))^{(1)/(5)}


1 + r = 1.034

Then


r = 1.034 - 1 = 0.034

The required interest rate would be of 3.4% a year.

User Arran
by
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