Question

A+10 u charge and a -10 4C (1 HC - 106 C), at a distance of 0.3 m,

A. Repel each with a force of 10 N
B. Attract each other with a force of 10 N
C. Repel each other with a force of 20 N
D. Attract each other with a force of 20 N

If anyone knows what’s going on here please help

Answer 1

B. Attract each other with a force of 10 newtons.

Step-by-step explanation:

Statement is incorrectly written. The correct form is: A
`+10\,\mu C` charge and a
`-10\,\mu C` at a distance of 0.3 meters.

The two particles have charges opposite to each other, so they attract each other due to electrostatic force, described by Coulomb's Law, whose formula is described below:

`F = (\kappa \cdot |q_(A)|\cdot |q_(B)|)/(r^(2))` (1)

Where:

`F` - Electrostatic force, in newtons.

`\kappa` - Electrostatic constant, in newton-square meters per square coulomb.

`|q_(A)|,|q_(B)|` - Magnitudes of electric charges, in coulombs.

`r` - Distance between charges, in meters.

If we know that
`\kappa = 8.988* 10^(9)\,(N\cdot m^(2))/(C^(2))`,
`|q_(A)| = |q_(B)| = 10* 10^(-6)\,C` and
`r = 0.3\,m`, then the magnitude of the electrostatic force is:

`F = (\kappa \cdot |q_(A)|\cdot |q_(B)|)/(r^(2))`

`F = 9.987\,N`

In consequence, correct answer is B.