Question

A water balloon weighing 4.5 N rests on a table. The balloon has an area of 2.6 x 10-3

m² in contact with the table. What pressure does the balloon exert on the table?

Answer 1

the pressure the balloon exerts on the table is 1,730.77 N/m²

Step-by-step explanation:

Given;

weight of the water balloon, F = 4.5 N

area of the balloon, A = 2.6 x 10⁻³ m²

The pressure the balloon exerts on the table is calculated as follows;

`P = (F)/(A)`

substitute the given values and solve for pressure, P;

`P = (4.5)/(2.6 * 10^(-3)) \\\\P = 1,730.77 \ N/m^2`

Therefore, the pressure the balloon exerts on the table is 1,730.77 N/m²