Question

Which are the solutions of x^2 = 19x + 1?

Answer 1

B

x₁ =
`(19-√(365))/(2)`, x₂ =
`(19+√(365) )/(2)`

Explanation:

Answer 2

x =
`(19+√(365))/(2), (19-√(365))/(2)`

Explanation:

1. Move everything to one side of the equation.

x^2 - 19x - 1 = 0

2. Use the quadratic formula where a = 1, b = -19, and c = -1.

x = (-b +- sqrt(b^2-4ac)) / 2a

If you plug those numbers into that formula, you will get the result listed above