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A sample of O2 occupies 75 L at 1 atm. If the volume of the

sample doubles, what is the new pressure of Oz?

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Answer:

the new pressure of Oz is 0.5 atm

Step-by-step explanation:

The computation of the new pressure of Oz is shown below:

Given that

Original pressure of O2 (P1) = 1 atm

And, the Original volume of oxygen O2 (V1) = 75L

Now

New pressure of O2 (P2) = ?

And, the New volume of O2 (V2) = 2V1 i.e

= (2 × 75L)

= 150L

Here we applied the Boyle's law formula

P1V1 = P2V2

1 atm × 75L = P2 × 150L

75 atm × L = 150L ×P2

Now Divide both sides by 150L to get P2

75 atm × L ÷ 150L = 150L × P2 ÷ 150L

0.5 atm = P2

Hence, the new pressure of Oz is 0.5 atm

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