Question

MgCl2 (aq) + K2SO4 (aq) --> 2KCl (aq) + MgSO4 (s)

how many moles of potassium chloride are produced from 4.8 moles of magnesium chloride

Answer 1

`\boxed {\boxed {\sf 9.6 \ mol \ KCl}}`

Step-by-step explanation:

We must use stoichiometry to solve this, which is the calculation of reactants and products in a reaction using ratios.

Let's analyze the reaction given.

`MgCl_2 _((aq)) + K_2SO_4 _((aq)) \rightarrow 2KCl _((aq)) + MgSO_4 _((s))`

Now, look at the coefficients, or numbers in front of the molecule formulas. If there isn't a coefficient, then a 1 is implied.

We want to find how many moles of potassium chloride (KCl) are produced from 4.8 moles of magnesium chloride (MgCl₂). Check the coefficients for these molecules.

• MgCl₂: no coefficient= coefficient of 1
• KCl: coefficient of 2

The coefficient represents the number of moles. Therefore, 1 mole of magnesium chloride produces 2 moles of potassium chloride. We can set up a ratio using this information.

`\frac { 1 \ mol \ MgCl_2} {2 \ mol \ KCl}`

Multiply by the given number of moles of magnesium chloride: 4.8

`4.8 \ mol \ MgCl_2 *\frac { 1 \ mol \ MgCl_2} {2 \ mol \ KCl}`

Flip the ratio so the moles of magnesium chloride cancel out.

`4.8 \ mol \ MgCl_2 *\frac {2 \ mol \ KCl} { 1 \ mol \ MgCl_2}`

`4.8 *\frac {2 \ mol \ KCl} { 1 \ } }`

`4.8 * {2 \ mol \ KCl}`

`9.6 \ mol \ KCl`

9.6 moles of potassium chloride are produced from 4.8 moles of magnesium chloride.