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What mass of iron (ciron= 0.11 cal/g°C) would need 1450 cal of energy in order to raise its temperature by 19.7°C
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What mass of iron (ciron= 0.11 cal/g°C) would need 1450 cal of energy in order to raise its temperature by 19.7°C

User Flesk
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Answer: m=Q/c*\Delta TQ/c∗ΔT = 1450cal/(0.11cal/g* 19.7ºC)=669.12 g1450cal/(0.11cal/g∗19.7ºC)=669.12g

Answer: 669.12g iron.

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User Kinkajou
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