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Find the dimensions and maximum area of a rectangle if the perimeter is 52

User Energya
by
3.1k points

1 Answer

0 votes

Answer: l

=

16

,

b

=

10

Step-by-step explanation:

Step-by-step explanation:

Perimeter of rectangle is

p

=

2

(

l

+

b

)

=

52

,

l

is length and

b

is breadth.

Area of rectangle is

A

=

l

b

=

160

l

=

160

b

;

2

(

160

b

+

b

)

=

52

or

(

160

b

+

b

)

=

26

or

160

+

b

2

b

=

26

or

160

+

b

2

=

26

b

or

b

2

26

b

+

160

=

0

or

b

2

16

b

10

b

+

160

=

0

or

b

(

b

16

)

10

(

b

16

)

=

0

or

(

b

16

)

(

b

10

)

=

0

b

=

16

or

b

=

10

If

b

=

16

;

l

=

160

16

=

10

and if

b

=

10

;

l

=

160

10

=

16

The dimension of rectangle is

l

=

16

,

b

=

10

[Ans]

User Ben Kelly
by
3.1k points