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What is the Ka of a 0.0592 M solution of hydrofluoric acid (HF) with a pH of 6.90
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What is the Ka of a 0.0592 M solution of hydrofluoric acid (HF) with a pH of 6.90

User Leighann
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2 Answers

4 votes

Answer: 2.7 x 10^-13

Step-by-step explanation:

User Sashaboulouds
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6 votes

Answer:

2.7*10^-13

coefficient= 2.7

exponent= -13

Step-by-step explanation:

User Vier
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5.7k points
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