What is the Ka of a 0.0592 M solution of hydrofluoric acid (HF) with a pH of 6.90

asked Jul 14, 2022 181k views

4 votes

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4 votes

Answer: 2.7 x 10^-13

Step-by-step explanation:

Sashaboulouds answered Jul 14, 2022

7.0k points

6 votes

Answer:

2.7*10^-13

coefficient= 2.7

exponent= -13

Step-by-step explanation:

Vier answered Jul 17, 2022

by Vier

7.3k points

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