Question

At some temperature for the equilibrium PX3(g) + X2(g) # PX5(g) the equilibrium constant is 0.74. At the same temperature the equilibrium constant for PX5(9) + PX3(g) X2(g) is​

Answer 1

Answer: The equilibrium constant for
`PX_5(g)\rightarrow PX_3(g)+X_2(g)` is 1.35

Step-by-step explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
`K_c`

For the given chemical reaction:

`PX_3(g)+X_2(g)\rightarrow PX_5(g)`

The expression for
`K_c` is written as:

`K_c=([PX_5]^1)/([PX_3]^1[X_2]^1)`

`0.74=([PX_5]^1)/([PX_3]^1[X_2]^1)`

For the reverse chemical reaction:

`PX_5(g)\rightarrow PX_3(g)+X_2(g)`

The expression for
`K_c'` is written as:

`K_c'=([PX_3]^1[X_2]^1)/([PX_5]^1)`

`K_c'=(1)/(K_c)=(1)/(0.74)=1.35`

The equilibrium constant for
`PX_5(g)\rightarrow PX_3(g)+X_2(g)` is 1.35