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PLEASE SOMEONE HELP ME WITH THIS. NO LIN.KS!!!!!​

PLEASE SOMEONE HELP ME WITH THIS. NO LIN.KS!!!!!​-example-1

2 Answers

3 votes

Answer:

Whatever he just answered

Explanation:

1.

centre(h,k)=(-13,9)

radius (r)=6

we have

equation of the circle is

(x-h)²+(y-k)²=r²

(x+13)²+(y-9)²=6²

(x+13)²+(y-9)²=36you can write this equation too

x²+26x+169+y²-18y+81=36

x²+y²+26x-18y+169+81-36=0

x²+y²+26x-18y +214=0

is a required equation of the circle.

2.

centre(h,k)=(1,-1)

radius (r)=11

we have

equation of the circle is

(x-h)²+(y-k)²=r²

(x-1)²+(y+1)²=11²

(x-1)²+(y+1)²=121

you can write this equation too

x²-2x+1+y²+2y+1=121

x²+y²-2x+2y=121-2

x²+y²-2x+2y=119

is a required equation of the circle.

3.

centre (h,k)=(3,1)

radius (r)=4units.

we have

equation of the circle is

(x-h)²+(y-k)²=r²

(x-3)²+(y-1)²=4²

(x-3)²+(y-1)²=16 is a required equation.

4.

centre(h,k)=(4,-2)

radius (r)=3

we have

equation of the circle is

(x-h)²+(y-k)²=r²

(x-4)²+(y+2)²=3²

(x-4)²+(y+2)²=9

you can write this equation too

User Imelda
by
8.7k points
6 votes

Answer:

1.

centre(h,k)=(-13,9)

radius (r)=6

we have

equation of the circle is

(x-h)²+(y-k)²=r²

(x+13)²+(y-9)²=6²

(x+13)²+(y-9)²=36you can write this equation too

x²+26x+169+y²-18y+81=36

x²+y²+26x-18y+169+81-36=0

x²+y²+26x-18y +214=0

is a required equation of the circle.

2.

centre(h,k)=(1,-1)

radius (r)=11

we have

equation of the circle is

(x-h)²+(y-k)²=r²

(x-1)²+(y+1)²=11²

(x-1)²+(y+1)²=121

you can write this equation too

x²-2x+1+y²+2y+1=121

x²+y²-2x+2y=121-2

x²+y²-2x+2y=119

is a required equation of the circle.

3.

centre (h,k)=(3,1)

radius (r)=4units.

we have

equation of the circle is

(x-h)²+(y-k)²=r²

(x-3)²+(y-1)²=4²

(x-3)²+(y-1)²=16 is a required equation.

4.

centre(h,k)=(4,-2)

radius (r)=3

we have

equation of the circle is

(x-h)²+(y-k)²=r²

(x-4)²+(y+2)²=3²

(x-4)²+(y+2)²=9

you can write this equation too

User Modasser
by
9.7k points

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