Answer:
:
1.
centre(h,k)=(-13,9)
radius (r)=6
we have
equation of the circle is
(x-h)²+(y-k)²=r²
(x+13)²+(y-9)²=6²
(x+13)²+(y-9)²=36you can write this equation too
x²+26x+169+y²-18y+81=36
x²+y²+26x-18y+169+81-36=0
x²+y²+26x-18y +214=0
is a required equation of the circle.
2.
centre(h,k)=(1,-1)
radius (r)=11
we have
equation of the circle is
(x-h)²+(y-k)²=r²
(x-1)²+(y+1)²=11²
(x-1)²+(y+1)²=121
you can write this equation too
x²-2x+1+y²+2y+1=121
x²+y²-2x+2y=121-2
x²+y²-2x+2y=119
is a required equation of the circle.
3.
centre (h,k)=(3,1)
radius (r)=4units.
we have
equation of the circle is
(x-h)²+(y-k)²=r²
(x-3)²+(y-1)²=4²
(x-3)²+(y-1)²=16 is a required equation.
4.
centre(h,k)=(4,-2)
radius (r)=3
we have
equation of the circle is
(x-h)²+(y-k)²=r²
(x-4)²+(y+2)²=3²
(x-4)²+(y+2)²=9
you can write this equation