Question

56x7y5, if x+0 and y#.0?

Which expression is equivalent to V
OA. 2x2y7xy2
OB. 8x4/7x472
Oc. 8 x 27 Try2
OD. 2244 297

Answer 1

B) answer is there

Answer 2

A is the answer.

Explanation:

We have

`\sqrt[3]{56 {x}^(7) {y}^(5) }`

Factor the radical by taking perfect squares of the real numbers and the exponents.

56 can be made up of perfect 8, x^7 can be made up of x^6 and y^5 can be made up of y^3. So we get

`\sqrt[3]{8 {x}^(6) {y}^(3) * \sqrt{7xy {}^(2) } }`

Take the cube root of 8x^6y^3.

Which is 2x^2y.

`2 {x}^(2) y \sqrt[3]{7xy {}^(2) }`

A is the answer.