Question

According to the reaction, below, how many grams of aluminum are needed to react fully with 100 grams of sulfur? 2AL + 3s - Al2S3

Answer 1

Answer: 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.

Step-by-step explanation:

To calculate the moles :

`\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of} S=(100g)/(32g/mol)=3.125moles`

The balanced chemical equation is:

`2Al+3S\rightarrow Al_2S_3`

According to stoichiometry :

3 moles of
`S` require = 2 moles of
`Al`

Thus 3.125 moles of
`S` will require=
`(2)/(3)* 3.125=2.08moles` of
`Al`

Mass of
`Al=moles* {\text {Molar mass}}=2.08moles* 27g/mol=56.2g`

Thus 56.2 g of Aluminium is needed to react fully with 100 grams of sulphur.