Question

a study of the effects of exercis used rats bred to have high or low capacity for exercise. The 8 high capacity rats had mean blood pressure 89 mm Hg and variance 81; the 8 low-capacity rats had mean blood pressure 105 mm Hg with variance 169. What is the value of the two-sample t statistic for comapring the two population means

Answer 1

`t=-2.86`

Explanation:

From the question we are told that:

Sample 1
`n_1=8`

Sample 1 mean blood pressure
`\=x_1=89mmHg`

Sample 1 variance
`\sigma_1=81`

Sample 2
`n_2=8`

Sample 2 mean blood pressure
`\=x_2=105mmHg`

Sample 2 variance
`\sigma_2=169`

Generally the equation for the test of statistic is mathematically given by

`t=\frac{\=x_1-\=x_2}{\sqrt{(\sigma_2)/(n_1)+(\sigma_2)/(n_2) } }`

`t=\frac{89-105}{\sqrt{(81)/(8)+(169)/(8) } }`

`t=-2.86`

therefore the samples test for comparing the two population means

`t=-2.86`