Question

As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted on the floor by the heel if it has an area of 1.45 cm2 and the woman's mass is 53.0 kg. Express the force in N/m2 and lb/in2. (In the early days of commercial flight, women were not allowed to wear high-heeled shoes because aircraft floors were too thin to resist such large pressures.)

Answer 1

The correct answer is "517.7 lb/in²".

Step-by-step explanation:

The given values are:

Woman's mass,

m = 53 kg

Area,

A = 1.45 cm²

=
`1.45* 10^(-4)` m²

Now,

The weight of woman will be:

⇒
`W=mg`

On substituting the values, we get

⇒
`=53* 9.8`

⇒
`=519.4 \ N`

Pressure will be:

⇒
`P=(W)/(A)`

⇒
`=(519.4)/(1.45* 10^(-4))`

⇒
`=3.57* 10^6 \ N/m^2`

or,

⇒
`=3.57* 10^6 \ Pa`

As we know,

⇒ 1 pound per sq. inch = 6895 Pascal's

hence,

⇒
`P=(3.57* 10^6)/(6895)`

⇒
`=517.7 \ lb/in^2`