Question

Be sure to answer all parts. For an aqueous solution of sodium chloride (NaCl), determine the molarity of 4.05 L of a solution that contains 195 g of sodium chloride. M Determine the volume of this solution that would contain 4.63 moles of sodium chloride. L Determine the number of moles of sodium chloride in 25.35 L of this solution. mol

Answer 1

`0.824\ \text{M}`

`5.62\ \text{L}`

`20.89\ \text{mol}`

Step-by-step explanation:

Molar mass of NaCl = 58.44 g/mol

Mass of NaCl = 195 g

Volume of solution = 4.05 L

Molarity of solution is

`(195)/(4.05)* (1)/(58.44)=0.824\ \text{M}`

The molarity of the solution is
`0.824\ \text{M}`

Moles of NaCl = 4.63 mol

Volume is given by

`(4.63)/(0.824)=5.62\ \text{L}`

The volume of the solution that contains the required amount NaCl is
`5.62\ \text{L}`

Volume of solution =
`25.35\ \text{L}`

Moles of solution is given by

`0.824* 25.35=20.89\ \text{mol}`

The number of moles of NaCl is
`20.89\ \text{mol}`.