180k views
4 votes
The residents of a certain dormitory have collected the following data: People who live in the dorm can be classified as either involved in a relationship or uninvolved. Among involved people, 15 percent experience a breakup of their relationship every month. Among uninvolved people, 15 percent enter into a relationship every month. What is the steady-state percentage of residents who are uninvolved

User Unkmas
by
6.6k points

1 Answer

4 votes

Answer:

the steady-state percentage of residents who are uninvolved is 0.5

Explanation:

Given the data in the question;

let N represent total number of people in the dormitory

I represent people involved in a relationship

and U represent people uninvolved in a relationship.

so

N = I + U

I = N - U ------ let this be equation 1

Rate of Uninvolved = U/N

now, given that rate of break ups B = 15% every month = 0.15

rate of entering into relationship R = 15% every month = 0.15

Now, the steady state condition is;

RU = BI ------- let this be equation 2

such that uninvolved rate is constant.

we input equation 1 into 2;

RU = B( N - U )

we divide both sides by N

RU/N = B( N/N - U/N )

RU/N = B( 1 - U/N )

U/N = B / (B + R)

so we substitute

U/N = 0.15 / (0.15 + 0.15)

U/N = 0.15 / 0.3

U/N = 0.5

Therefore, the steady-state percentage of residents who are uninvolved is 0.5

User Rdp
by
6.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.