Answer:
the steady-state percentage of residents who are uninvolved is 0.5
Explanation:
Given the data in the question;
let N represent total number of people in the dormitory
I represent people involved in a relationship
and U represent people uninvolved in a relationship.
so
N = I + U
I = N - U ------ let this be equation 1
Rate of Uninvolved = U/N
now, given that rate of break ups B = 15% every month = 0.15
rate of entering into relationship R = 15% every month = 0.15
Now, the steady state condition is;
RU = BI ------- let this be equation 2
such that uninvolved rate is constant.
we input equation 1 into 2;
RU = B( N - U )
we divide both sides by N
RU/N = B( N/N - U/N )
RU/N = B( 1 - U/N )
U/N = B / (B + R)
so we substitute
U/N = 0.15 / (0.15 + 0.15)
U/N = 0.15 / 0.3
U/N = 0.5
Therefore, the steady-state percentage of residents who are uninvolved is 0.5