Answer:
4.5L of gas are produced
Step-by-step explanation:
Based on the reaction:
Zn + H2SO4 → ZnSO4 + H2(g)
Where 1 mole of Zn reacts with 1 mole of sulfuric acid to produce 1 mole of H2, the gas
To solve this question we must find the moles of each reactant in order to find limiting reactant and, thus, the moles of H2 produced. Then using PV=nRT we can find the volume of the gas:
Moles Zn -Molar mass: 65.38g/mol-
13g * (1mol / 65.38g) = 0.20 moles Zn
Moles H2SO4 -Molar mass: 98g/mol-
400g * 10% = 40g H2SO4 * (1mol / 98g) = 0.41 moles H2SO4
As the ratio of the reaction is 1:1, the limiting reactant is Zn and the moles produced of H2 are 0.20 moles
Using PV = nRT; V = nRT/ P
Where V is the volume of the gas
n are the moles = 0.20 moles
R is gas constant = 0.082atmL/molK
T is absolute temperature = 273.15K at STP
P is pressure = 1atm at STP
V = 0.20mol*0.082atmL/molK*273.15K / 1atm
V = 4.5L of gas are produced