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50 POINTS if p=(-2,-1) and Q=(-6,-3) are the endpoints of the diameter of a circle, find the equation of the circle

User Flamenco
by
3.8k points

2 Answers

5 votes

Answer:

(x+4)^2 + (y+2)^2 = 5

Step-by-step explanation:

Using the midpoint formula, we find that the center of the circle is (-4, -2). We also calculate using the distance formula that between the two points is
√(2\\0)or
2√(5\\\\).

Because we found the diameter, to find the radius we divide by two, getting
√(5\\\\).

Now that we have the center, (-4, -2), and the distance from the center to the radius, we can put the information into the circle equation:

(x-h)^2 + (y-k)^2 = r^2

This becomes:

(x+4)^2 + (y+2)^2 = 5

User DanMunoz
by
3.3k points
5 votes

Answer:

-4 , -2 , 5

Step-by-step explanation:

(x-(-4))^2+(y-(-2))^2=5

since 2 negatives equal a positive, - -4 = +4

same thing for -2

(x+4)^2+(y+2)^2=5

User Gennady Dogaev
by
3.7k points