Question

Calculate the grams of solute in each of the following solution: 278 mL of 0.038 M Fe2(SO4)3

Answer 1

Answer: 4.22 grams of solute is there in 278 ml of 0.038 M
`Fe_2(SO_4)_3`

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

`Molarity=(n)/(V_s)`

where,

n = moles of solute

`V_s` = volume of solution in L

Now put all the given values in the formula of molality, we get

`0.038M=(n)/(0.278L)`

`n=0.0105mol`

mass of
`Fe_2(SO_4)_3` =
`moles* {\text {Molar Mass}}=0.0105* 399.88g/mol=4.22g`

Thus 4.22 grams of solute is there in 278 ml of 0.038 M
`Fe_2(SO_4)_3`