Answer:
31m/s
Explanation:
Using the equation of motion
v² = u² + 2gH
H is the height of fall = 49m
g is the acceleration due to gravity = 9.8m/s²
u is the initial velocity = 0m/s
v² = 0² + 2(9.8)(49)
v² = 960.4
v = √960.4
v = 30.9m/s
v ≈ 31m/s
Hence the velocity of water at the turbine is 31m/s