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Sphere A has radius 6 inches and sphere B has diameter 14 inches. Find the ratio of the surface area of A to the surface area of B.​

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Answer:

the ratio of the surface area of A to the surface area of B is 36 ÷ 49

Explanation:

The computation of the ratio of the surface area of A to the surface area of B is shown below;

= Surface area of the sphere a ÷ surface area of the sphere b

= 4πr^2 ÷ 4πr^2

= 6^2 ÷ 14 ÷ 2^2

= 36 ÷ 49

hence, the ratio of the surface area of A to the surface area of B is 36 ÷ 49

The same would be considered and relevant too

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