Given:
The figure of a right angle triangle with hypotenuse 10 and two angles

To find:
The lengths of the legs.
Solution:
Two angles are given. By using the angle sum property, the third angle is:
Third angle =
=

Base angles are equal it means the given triangle is an isosceles right triangle. So, the lengths of both legs are equal.
Let x be the lengths of both legs. Then by using Pythagoras theorem, we get





Taking square root on both sides, we get



The side length cannot be negative. So, the only value of x is
.
Therefore, the length of the both legs is
units.