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34 votes
A. Triangle ABC and CDA by angle-side-angle

B. ABC and CDA by side-angle-side

C. ABE and CDE by angle-side-angle

D ABE and CDE by side-angle-side

A. Triangle ABC and CDA by angle-side-angle B. ABC and CDA by side-angle-side C. ABE-example-1
User Carlos Castillo
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1 Answer

19 votes
19 votes

Answer:

D. ABE and CDE by SAS Theorem (Side-Angle-Side)

Explanation:

First lets establish that by the Vertical Angles Theorem, when two lines intersect, the vertical angles created are congruent. Thus, ∠AED is congruent to ∠CED. Now, we need to figure out which pair of triangles Craig is referring to. We know that to figure out if two triangles are congruent, they must have three congruent of either sides and/or angles. We know that Craig can't be referring to triangle AED and BEC because the angle of their vertex's are not congruent. We also know that Craig can't be referring to triangles ABC and CDA because although they share a similar side (Indicated by the one tic mark), they don't have anything else that is congruent.

Thus, this is why triangles ABE and CDE are the triangles Craig is referring to. Both of these triangles have congruent vertex because of the vertical angles theorem. Both of these triangles also share the same sides as indicated by the one and two tic marks. Since there are two sides and an included angle, triangles ABE and CDE are congruent by the SAS theorem.

Finally, the way Craig can prove that AB is parallel to CD is by the CPCTC theorem. The CPCTC theorem states that corresponding parts of congruent triangles are congruent. Since we already established that the two triangles are congruent, we can safely say that line AB is parallel to CD.

User Jackie Shephard
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