Question

Help guys I only have 18 minutes left!!!!!!

Answer 1

Given:

The equation of a circle is:

`(x-3)^2+y^2=32`

To find:

Center and the circumference of the circle.

Solution:

The standard form of a circle is:

`(x-h)^2+(y-k)^2=r^2` ...(i)

Where, (h,k) is center and r is the radius.

We have,

`(x-3)^2+y^2=32` ...(ii)

On comparing (i) and (ii), we get

`h=3,y=0,r=√(32)`

So, the center of the circle is (3,0) and the radius of the circle is
`√(32)`.

Now, the circumference of the circle is:

`C=2\pi r`

`C=2(3.14)(√(32))`

`C=35.525045`

`C\approx 35.5`

Therefore, the circumference of the circle is about 35.5 units.