1 Answer

Gichamba · Answer 1 · 2022-07-18T05:52:18+0000

Given:

The equation of a circle is:

(x-3)^2+y^2=32

To find:

Center and the circumference of the circle.

Solution:

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2 ...(i)

Where, (h,k) is center and r is the radius.

We have,

(x-3)^2+y^2=32 ...(ii)

On comparing (i) and (ii), we get

h=3,y=0,r=√(32)

So, the center of the circle is (3,0) and the radius of the circle is
.

Now, the circumference of the circle is:

$C=2\pi r$

C=2(3.14)(√(32))

C=35.525045

$C\approx 35.5$

Therefore, the circumference of the circle is about 35.5 units.

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