Complete question:
Part A:) The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c , space-dock personnel measure the rocket ship to be 43.3 m long. The rocket ship Adventure travels to a star many light-years away, then turns around and returns at the same speed. When it returns to the space dock, who would have aged less: the space-dock personnel or ship's captain?
Part B: What is the momentum of a proton traveling at 0.62 c ?
Answer
a)Who would have aged less=The Captain would have aged less
b)
![p=3.96*10^(-19)kgm/s](https://img.qammunity.org/2022/formulas/physics/college/zdknaj7o45p9ip9ufz0k7hcou813u0a5yh.png)
Step-by-step explanation:
From the question we are told that
Length measured by captain
![l_c=50m](https://img.qammunity.org/2022/formulas/physics/college/j41v80glqn416j4somq9h8y481uxh6od1q.png)
Speed of rocket past tje space dock
![V=0.5c](https://img.qammunity.org/2022/formulas/physics/college/43zzu88n8o1iaksu09ngnc1b0qmgpm8xtu.png)
Length measured by space-dock personnel
![l_c=43.3m](https://img.qammunity.org/2022/formulas/physics/college/fj0x0ngi3qd1c6mo81gqus5o5orj1m4ctz.png)
a)
Generally time moves slower when moving at speed of light, due to time dilation or variation.
Who would have aged less=The Captain would have aged less
b)
Generally the equation for Relativistic Momentum is mathematically given as
![p=(m*v)/(1 - v^2/c^2)](https://img.qammunity.org/2022/formulas/physics/college/cwz6s8b1uip2latun027to2cm3ocy7mqdh.png)
![p=(1.67*10^2-27*0.62*3.0*10^8))/(√( 1 -0.6^2))](https://img.qammunity.org/2022/formulas/physics/college/itmfg1d7piu4bb371e8pcq0y569hnhc939.png)
![p=3.96*10^(-19)kgm/s](https://img.qammunity.org/2022/formulas/physics/college/zdknaj7o45p9ip9ufz0k7hcou813u0a5yh.png)