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Let ​g(x)=3x−1 and ​f(x)=x2+1. Find ​(g◦​f)(−5​).

​(g◦​f)(−5​)=nothing ​(Simplify your​ answer.)

Let ​g(x)=3x−1 and ​f(x)=x2+1. Find ​(g◦​f)(−5​). ​(g◦​f)(−5​)=nothing ​(Simplify-example-1
User Markwilde
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3 votes

Answer:

-384

Explanation:

Solve for each function first.

g(-5) = 3(-5) - 1

g(-5) = -16

f(-5) = -5^2 + 1

f(-5) = -24

Multiply.

(fg)(-5) = (-16 x -24)

(fg)(-5) = -384

Not entirely sure if this is correct but this seemed the most obvious way to do it so I did it. Let me know if I'm wrong.

User Jmav
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