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Eva payrolls for on a number cube and the number of cubes roll 24 times then what is a reasonable prediction for the number of successful Rolls

User Acattle
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Answer:

The reasonable prediction for successful rolls is 4.

Explanation:

Assuming the rolling cube is a fair 6 sided cube, so the probability of success of one roll is given as


P(Success)=(Number\ of\ successful\ events)/(Number\ of\ total\ events)


P(Success)=(1)/(6)

The total success is given as


P(Total\ Success)=P(Success)* Number\ of\ events

For 24 rolls it is given as


P(Total\ Success)=P(Success)* Number\ of\ events\\P(Total\ Success)=(1)/(6)* 24\\P(Total\ Success)=4

So the reasonable prediction for successful rolls is 4.

User Llistes Sugra
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