Question

In the Eqn: [3 Fe + 2 O2 → Fe3O4], How many grams of Fe will be needed to react with 6.85 mol O2 ?

Answer 1

575g

Step-by-step explanation:

Mole ratio Fe : O2 = 3:2

so moles of Fe = 1.5 x 6.85 = 10.275 moles

mass=moles x Ar

Ar Fe= 56

mass = 10.275 x 56=575g