Question

A person starts running from 2 m/s to 6 m/s in 2 seconds.

Calculate the person's acceleration.
Var
Variables:
Solve:
F
Formula:

Answer 1

The person's acceleration is calculated using the formula a = Δv / Δt, with a change in velocity of 4 m/s over a period of 2 seconds, which results in an acceleration of 2 m/s^2.

Step-by-step explanation:

To calculate the person's acceleration, we need to use the formula a = Δv / Δt, where a is the acceleration, Δv is the change in velocity, and Δt is the change in time. In this case, the initial velocity (vi) is 2 m/s, the final velocity (vf) is 6 m/s, and the time taken (Δt) is 2 seconds.

First, we calculate the change in velocity (Δv):

Δv = vf - vi = 6 m/s - 2 m/s = 4 m/s

Next, we apply the formula for acceleration:

a = Δv / Δt = 4 m/s / 2 s = 2 m/s2

Therefore, the person's acceleration is 2 m/s2.

Answer 2

2 m/s²

Step-by-step explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 2 m/s

Final velocity (v) = 6 m/s

Time (t) = 2 s

Acceleration (a) =?

The acceleration of the person can be obtained as follow:

v = u + at

6 = 2 + (a×2)

6 = 2 + 2a

Collect like terms

6 – 2 = 2a

4 = 2a

Divide both side by 2

a = 4 / 2

a = 2 m/s²

Therefore, the acceleration of the person is 2 m/s²