8.0k views
0 votes
I play a gambling game in which I will win different amounts of money with different likelihood's. Suppose that I win X dollars with a probability of P(X) (if C is negative I am losing money). The distribution is as follows: what is the appropriate value of P?

1 Answer

2 votes

Answer:


p = 0.05

Explanation:

Given

See attachment for the distribution

Required

Find p

To find p, we make use of:


\sum P(x) = 1

So, we have:


0.50 + 0.25 + 0.13 + 0.07 + p = 1


0.95 + p = 1

Make p the subject


p = 1 - 0.95


p = 0.05

I play a gambling game in which I will win different amounts of money with different-example-1
User Ensar Bayhan
by
4.9k points