Answer:
46 ≤ n ≤ 60 ( C )
Explanation:
using the given null hypothesis to check if the samples differ from originally values
given that: frequency ( f ) ≥ 5
N = 600
hence : n * 0.11 ≥ 5
therefore : n ≥ 45.45
next : also n / N ≤ 0. 10
therefore: n ≤ 0.1 * 600
therefore all possible sizes will lie between
46≤n≤60