Question

Need help asappppppp​

Answer 1

Given:

The right triangular prism.

Height of prism = 28 in.

Hypotenuse of base = 25 in.

leg of base = 24 in.

To find:

The lateral surface area of the prism.

Solution:

Pythagoras theorem:

`Hypotenuse^2=Perpendicular^2+Base^2`

Using Pythagoras theorem in the base triangle, we get

`25^2=24^2+Base^2`

`625-576=Base^2`

`√(49)=Base`

`7=Base`

The perimeter of the triangular base is:

`P=7+25+24`

`P=56`

Lateral area of a triangular prism is:

`A=Ph`

Where, P is the perimeter of the triangular base and h is the height of the prism.

Putting
`P=56,h=28` in the above formula, we get

`A=56(28)`

`A=1568`

Therefore, the lateral area of the prism is 1568 in².