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Find the permitter of each polygon.

Find the permitter of each polygon.-example-1
User Pingless
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3 votes

Answer:

here you go Sofia

Explanation:

23.2 is one side of the triangle

21.7 is another

since the triangle goes around that circle perfectly two of the sides have to be the same

so the other side is also 21.7 just add them

21.7 + 21.7 + 23.2= 66.6 for the perimeter of the triangle

Area = ½[√(a^2 − b^2 ⁄4) × b]

Area = 1/2 [ sqrt(23.2^2 - 21.7^2 / 4 ) *21.7]

Area = 1/2 [ sqrt(538.24 - 470.89/4 ) *21.7]

Area = 1/2 [ sqrt( 420.5175 ) * 21.7]

Area = 1/2 [ 20.50652335 * 21.7 ]

Area = 1/2 [ 444.991556 ]

Area = 222.4957

now use that to find the radius of the circle

Area = 1/2 * r * trig perim

222.4957 = 1/2 * r * 66.6

6.681554 = r

now find the circumference of the circle ( perimeter of circle)

circ= 2
\pir

circ = 2
\pi6.681554

circ = 41.98144

User Saddam
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