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Answer:
see attached
Explanation:
Point A is arbitrarily located. We have drawn the circle on a grid, so have made points A and E on orthogonal axes through point O.
1. Point B can be anywhere on the circle except on line AO.
2. Making circle A have the same radius as circle O puts points C and D 120° apart.
3. In this diagram, OF bisects right angle EOA, so central angle EOF is 45°.