Question

How do you solve 3b(9b-27)=0

Answer 1

`b=3`, or
`0`

Explanation:

`\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0`

`b=0\quad \mathrm{or}\quad \:9b-27=0`

`9b-27=0`,
`\mathrm{Add\:}27\mathrm{\:to\:both\:sides}.`

`9b-27+27=0+27`

`9b=27`

`\mathrm{Divide\:both\:sides\:by\:}9`

`(9b)/(9)=(27)/(9)`

`b=3`

Answer 2

Answer:0

Step-by-step explanation:3b(-27 + 9b) = 0

(-27 * 3b + 9b * 3b) = 0

(-81b + 27b2) = 0