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The sum of three consecutive even numbers is 108. Write and evaluate an expression in terms of x to determine the smallest of the three numbers. Include parentheses in your expression.

1 Answer

4 votes

Answer:


34

Explanation:

Let the first number be
x

The next number be
2 more than the previous as it is an even number

The second number is
x+2

and the last number is
x+4

The sum of the numbers is
108, so the expression will be


x+(x+2)+(x+4)=108


\Rightarrow 3x+6=108


\Rightarrow x=(108-6)/(3)


\Rightarrow x=34

The smallest of the three numbers is
34.

User Ilan Klinghofer
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