Question

Amy pulls a spring with a spring constant k = 100 stretching it from its rest length of 0.10 m to 0.2

Answer 1

Amy pulls a spring with a spring constant k = 100 N/m, stretching it from its rest length of 0.10 m to 0.20 m.

What is the elastic potential energy stored in the spring?

Answer: 0.5 J

Answer 2

Elastic potential energy E = 0.5 J

Step-by-step explanation:

Let us assume we have to find the elastic potential energy stored in the spring.

Given: k = 100

change in the length of the spring x = 0.2-0.1 = 0.1 m

Elastic potential energy

E =
`(1)/(2) kx^2`

plugging the values we get

`E = 0.5*100*0.1^2\\=0.5 J`

Hence, Elastic potential energy E = 0.5 J