Question

Gaseous ammonia, NH3, is obtained from the reaction of gaseous hydrogen and gaseous nitrogen. According to this reaction, what volume, in L, of nitrogen is required to completely react with 25.0 L of hydrogen under STP conditions?

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Group of answer choices

8.32 mL

8.32 L

8.20 L

8.00 L

Answer 1

8.33 L .

Step-by-step explanation:

Hello there!

In this case, according to the given problem, it is possible to firstly write up the undergoing chemical reaction:

`3H_2+N_2\rightarrow 2NH_3`

Whereas the mole ratio of hydrogen to nitrogen is 3:1. In such a way, given that the mole ratios can be also applied in volume when the temperature and pressure remain unchanged, it is possible to compute the required volume of nitrogen from 25.0 L of hydrogen as shown below:

`25.0L\ H_2*(1L \ N_2)/(3L\ H_2)\\\\=8.33L`

Best regards!