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Solve by factoring

2n^2+12n+18

User Coolhand
by
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1 Answer

4 votes

Answer:

Explanation:

d/dn(2 n^2 + 12 n + 18) = 4 (n + 3)

Indefinite integral:

integral(18 + 12 n + 2 n^2) dn = (2 n^3)/3 + 6 n^2 + 18 n + constant

Global minimum:

min{2 n^2 + 12 n + 18} = 0 at n = -3

User Tim Schruben
by
8.5k points

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