Question

The latent heat of fusion for Aluminium is 3.97 x 105. How much energy would be required to melt 0.75 kg of it?

Answer 1

`E = 2.9775*10^5 J`

Step-by-step explanation:

Given: The latent heat of fusion for Aluminum is
`L = 3.97*10^5 J/Kg`

mass to be malted m = 0.75 Kg

Energy require to melt E = mL

`E = 3.97*10^5*0.75 = 2.9775*10^5 J`

Therefore, energy required to melt 0.75 Kg aluminum

`E = 2.9775*10^5 J`