Question

Solve the system of equations using subtraction. Equation 1: 3x-2y= -2 Equation 2: 3x + y = 10 The solution is (? ,?) HURRY PLEASE!!!!

Answer 1

the solution is x = 2 and y = 4 OR (2,4)

Explanation:

From the question

Equation 1: 3x-2y= -2

Equation 2: 3x + y = 10

Subtract equation 1 from equation 2, that is

3x + y = 10 - (3x -2y = -2)

You get

3x - 3x + y - (-2y) = 10 - (-2)

0 + y + 2y = 10 + 2

3y = 12

Divide both sides by 3

∴ y = 12/3

y = 4

Substitute the value of y into equation 2 to get x

3x + y = 10

3x + 4 = 10

Then,

3x = 10 - 4

3x = 6

Divide both sides by 3

∴ x = 6/3

x = 2

Hence, the solution is x = 2 and y = 4