Question

What is the total number of grams of HI in 0.500 liter of

1.00 M HI?
64.0 g
128 g
1.00 g
0.500 g

Answer 1

The amount of HI is "64 grams".

Step-by-step explanation:

The given values are:

Volume,

= 0.500 L

Molarity,

= 1.00 H

Molar mass of HI,

= 128

Now,

The moles of HI will be:

=
`Molarity* Volume`

On substituting the values, we get

=
`1.00* 0.500`

=
`0.5 \ mol`

hence,

The amount of HI will be:

=
`Moles* Molar \ mass`

=
`0.5* 128`

=
`64 \ grams`