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Solve: log3(x)+log3(x-2)=log3(x+10)​

User StealthRT
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1 Answer

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log3 ( x ) + log3 ( x - 2 ) = log3 ( x + 10 )

log3 ( x )( x - 2 ) = log3( x + 10 )

log3 ( x^2 - 2x ) = log3( x + 10 )

x^2 - 2x = x + 10

x^2 - 3x - 10 = 0

( x - 5 )( x + 2 ) = 0 ==》x = 5 Or x = - 2

User MBarsi
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