Question

How many real solutions does the system have?

y = -3x - 1
y = x^2– 3x + 4
Enter your answer in the box

Answer 1

no real solutions

Explanation:

Substitute y:

-3x-1 = x^2 - 3x + 4

move terms to one side:

0 = x^2 + 5

x^2 = -5

x = ±√5i

no real solutions