Question

A tank containing water up to a depth of 650 mm is stationary. Find the force exerted by fluid of specific gravity 0.55 on the side of tank, width of tank is 1.5m. Ρ water = 1000 kg/m³:

Answer 1

3415.91 N

Step-by-step explanation:

We know pressure, P at depth, h is P = ρgh where ρ = density of fluid = specific gravity × density of water = 0.55 × 1000 kg/m³ = 550 kg/m³, g = acceleration due to gravity = 9.8 m/s² and h = depth of water = 650 mm = 0.650 m

So, P = ρgh

= 550 kg/m³ × 9.8 m/s² × 0.650 m

= 3503.5 N/m²

Now pressure P = F/A where F = force on the side of tank and A = area of side of tank = depth of water × width of tank = 0.650 m × 1.5 m = 0.975 m²

So, F = PA

= 3503.5 N/m² × 0.975 m²

= 3415.913 N

≅ 3415.91 N