Question

What is the molarity of a 100 mL solution that contains 2.00 g KCL

Answer 1

The molarity will be "0.26 M".

Step-by-step explanation:

The given values are:

Mass,

= 2.00 g

Volume of solution,

= 100 mL

or,

=
`(100)/(1000)`

=
`0.1 \ L`

Molar mass of KCl,

= 74.5 gm

Now,

Moles of KCl will be:

=
`(Given \ mass)/(Molar \ mass)`

=
`(2)/(74.5)`

=
`0.026`

hence,

The molarity will be:

=
`(Moles \ of \ solute)/(Volume \ of \ solution)`

On substituting the values, we get

=
`(0.026)/(0.1)`

=
`0.26 \ M`